# NCERT Solutions for Class 6 Maths Chapter 10 Mensuration InText Questions

These NCERT Solutions for Class 6 Maths Chapter 10 Mensuration InText Questions and Answers are prepared by our highly skilled subject experts.

## NCERT Solutions for Class 6 Maths Chapter 10 Mensuration InText Questions

NCERT In-text Question Page No. 206
Question 1.
Measure and write the length of the four sides of the top of your study table.
AB = …………… cm BC = ………….. cm
CD = ………….. cm DA = …………… cm

Now, the sum of the lengths of the four sides
= AB + BC + CD + DA
= ……….. cm + ……….. cm + ………….. cm + ……………. cm
= …………… cm
What is the perimeter?
Answer:
AB = 140 cm, BC = 80 cm,
AB = 140 cm, DA = 80 cm
∴ AB + BC + CD + DA
= 140 cm + 80 cm + 140 cm + 80 cm
= 140 cm
The perimeter 440 cm.
Note :This is an activity so the measures of AB, BC, CD and DA will be different for different table tops.

Question 2.
Measure and write the lengths of the four sides of a page of your notebook. The sum of the lengths of the four sides
= AB + BC + CD + DA
= ………….. cm + ………………. cm + ……………. cm + ……………. cm
= ……………… cm
What is the perimeter of the page?
Answer:
Please try yourself.

Question 3.
Meera went to a park 150 m long and 80 m wide. She took one complete round
on its boundary. What is the distance covered by her?
Answer:
The park is in the shape of rectangle.
Since she takes one complete round which is equal to perimeter of the rectangular park.
Perimeter of rectangular park
= 2 (length + breadth)
= 2 ( 150+ 80)
= 2 × 230
= 460 m
Therefore, the distance covered by her is 460m.

Question 4.
Find the perimeter of the following figures:
(a) Perimeter = AB + BC + CD + DA
= …………… + …………… + ……………. + ……………….+
= ………………

(b) Perimeter = AB + BC + CD + DA
= ……………. + …………. + ………….. + …………… +
= ……………..

(c) Perimeter = AB + BC + CD + DE + EF + FG + GH + HI+ IJ + JK+ KL + LA
= ……………… + ……………… + …………… + …………… +
……………… + …………….. + …………….. + ……………. +
……………. + …………….. + ……………. + …………….. +

(d) Perimeter=AB + BC + CD + DE + EF + FA
= ……………. + ……………. + ……………… + …………….. +
……………… + ……………. +
= ………………

Answer:
(a) AB = 40 cm, BC =10 cm,
AD = 10 cm and DC = 40 cm
∴ Perimeter = AB + BC + AD + DC
= 40 cm + 10 cm + 10 cm + 40 cm
= 100 cm

(b) AB = 5 cm, BC = 5 cm,
AD = 5 cm and AD = 5 cm
∴ Perimeter = AB + BC + CD + AD
= 5 cm + 5 cm + 5 cm + 5 cm = 20 cm

(c) Here, perimeter = AB + BC + CD + DE + EF + FG + GH + HI + IJ + JK + KL + LA
= 1 cm + 3 cm + 3 cm + 1 cm + 3 cm + 3cm + 1 cm + 3 cm + 3 cm + 1 cm + 3 cm + 3 cm = 28 cm

(d) Here, perimeter = AB + BC + CD + DE + EF + FA
= 100 m + 120 m + 90 m + 45 m + 60 m + 80 m = 495m

NCERT In-text Question Page No. 208
Question 1.
Find the perimeter of the following rectangle :

Answer:
Do yourself.

NCERT In-text Question Page No. 211
Question 1.
Find various objects from your surroundings which have regular shapes and find their perimeters.
Answer:
It is a project work. You can find objects having regular shapes such as a ‘name plae’ a road signal’, etc. Measure their sides and find perimeters.

NCERT In-text Question Page No. 215
Question 1.
Draw any circle on a graph sheet. Count the squares and use them to estimate the area of the circular region.
Answer:
It is an ‘activity’. Please do it yourself.

Question 2.
Trace shapes of leaves, flower petals and other such objects on the graph paper and find their areas.
Answer:
It is an ‘activity’. Please do it yourself.

NCERT In-text Question Page No. 217
Question 1.
Find the area of the floor of your classroom.
Answer:
This is an activity. Please do it yourself.

Question 2.
Find the area of any one door in your house.
Answer:
This is an activity. Please do it yourself.

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