{"id":27737,"date":"2021-07-01T16:35:02","date_gmt":"2021-07-01T11:05:02","guid":{"rendered":"https:\/\/mcqbooks.com\/?p=27737"},"modified":"2022-03-06T18:49:55","modified_gmt":"2022-03-06T13:19:55","slug":"ncert-solutions-for-class-8-maths-chapter-9-ex-9-2","status":"publish","type":"post","link":"https:\/\/mcqbooks.com\/ncert-solutions-for-class-8-maths-chapter-9-ex-9-2\/","title":{"rendered":"NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Ex 9.2"},"content":{"rendered":"

These NCERT Solutions for Class 8 Maths<\/a> Chapter 9 Algebraic Expressions and Identities Ex 9.2 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Exercise 9.2<\/h2>\n

Question 1.
\nFind the product of the following pairs of monomials
\n(i) 4, 7p
\n(ii) -4p, 7p
\n(iii) -4p, 7pq
\n(iv) 4p3<\/sup>, – 3p
\n(v) 4p, 0
\nSolution:
\n(i) 4 \u00d7 7p
\n= (4 \u00d7 7)p
\n= 28p<\/p>\n

(ii) -4p \u00d7 7p
\n= {(-4) \u00d7 7} \u00d7 (p \u00d7 p)
\n= (-28) \u00d7 p2<\/sup>
\n= -28p2<\/sup><\/p>\n

(iii) -4p \u00d7 7pq
\n= {(-4) \u00d7 7} \u00d7 {p \u00d7 (pq)}
\n= -28 \u00d7 (p \u00d7 p \u00d7 q)
\n= -28p2<\/sup>q<\/p>\n

\"NCERT<\/p>\n

(iv) 4p3<\/sup> \u00d7 -3p
\n= {4 \u00d7 (-3)} \u00d7 (p3<\/sup> \u00d7 p)
\n= -12 \u00d7 (p4<\/sup>)
\n= -12p4<\/sup><\/p>\n

(v) 4p \u00d7 0
\n= (4 \u00d7 0) \u00d7 p
\n= 0 \u00d7 p
\n= 0<\/p>\n

Question 2.
\nFind the areas of rectangles, with the following pairs of monomials as their lengths and breadths respectively.
\n(p, q); (10m, 5n); (20x2<\/sup>, 5y2<\/sup>); (4x, 3x2<\/sup>); (3mn, 4np)
\nSolution:
\n(i) (p, q)
\nArea of the rectangle = length \u00d7 breadth
\n= p x q
\n= pq<\/p>\n

(ii) (10m, 5n)
\nArea of the rectangle = length \u00d7 breadth
\n= 10m \u00d7 5n
\n= (10 \u00d7 5) \u00d7 (m \u00d7 n)
\n= 50 \u00d7 mn
\n= 50mn<\/p>\n

(iii) 20x2<\/sup>, 5y2<\/sup>
\nArea of the rectangle = length \u00d7 breadth
\n= 20x2<\/sup> \u00d7 5y2<\/sup>
\n= (20 \u00d7 5) \u00d7 (x2<\/sup> \u00d7 y2<\/sup>)
\n= 100 \u00d7 x2<\/sup>y2<\/sup>
\n= 100x2<\/sup>y2<\/sup><\/p>\n

\"NCERT<\/p>\n

(iv) (4x, 3x2<\/sup>)
\nArea of the rectangle = length \u00d7 breadth
\n= 4x \u00d7 3x2<\/sup>
\n= (4 \u00d7 3) \u00d7 (x \u00d7 x2<\/sup>)
\n= 12 \u00d7 x3<\/sup>
\n= 12x3<\/sup><\/p>\n

(v) (3mn, 4np)
\nArea of the rectangle = length \u00d7 breadth
\n= 3mn \u00d7 4np
\n= (3 \u00d7 4) \u00d7 (mn \u00d7 np)
\n= 12 \u00d7 m \u00d7 (n \u00d7 n) \u00d7 p
\n= 12 \u00d7 m \u00d7 n2<\/sup> \u00d7 p
\n= 12mn2<\/sup>p<\/p>\n

Question 3.
\nComplete the table products.
\n\"NCERT
\nSolution:
\n\"NCERT<\/p>\n

Question 4.
\nObtain the volume of rectangular boxes with the following length, breadth and height respectively.
\n(i) 5a, 3a2<\/sup>, 7a4
\n(ii) 2p, 4q, 8r
\n(iii) xy, 2x2<\/sup>y, 2xy2<\/sup>
\n(iv) a, 2b, 3c
\nSolution:
\n(i) 5a, 3a2<\/sup>, 7a4<\/sup>
\nVolume of the rectangular box = length \u00d7 breadth \u00d7 height
\n= (5a) \u00d7 (3a2<\/sup>) \u00d7 (7a4<\/sup>)
\n= (5 \u00d7 3 \u00d7 7) \u00d7 (a \u00d7 a2<\/sup> \u00d7 a4<\/sup>)
\n= 105a7<\/sup><\/p>\n

\"NCERT<\/p>\n

(ii) 2p, 4q, 8r
\nVolume of the rectangular box = Length \u00d7 Breadth \u00d7 Height
\n= 2p \u00d7 4q \u00d7 8r
\n= (2 \u00d7 4 \u00d7 8) \u00d7 (p \u00d7 q \u00d7 r)
\n= 64pqr<\/p>\n

(iii) xy; 2x2<\/sup>y; 2xy2<\/sup>
\nVolume of the rectangular box = length \u00d7 breadth \u00d7 height
\n= xy \u00d7 2x2<\/sup>y \u00d7 2xy2<\/sup>
\n= (1 \u00d7 2 \u00d7 2) \u00d7 (x \u00d7 x2<\/sup> \u00d7 x) \u00d7 (y \u00d7 y \u00d7 y2<\/sup>)
\n= 4 \u00d7 x4<\/sup> \u00d7 y4<\/sup>
\n= 4x4<\/sup>y4<\/sup><\/p>\n

(iv) a, 2b, 3c
\nVolume of the rectangular box = length \u00d7 breadth \u00d7 height
\n= a \u00d7 2b \u00d7 3c
\n= (1 \u00d7 2 \u00d7 3) \u00d7 (a \u00d7 b \u00d7 c)
\n= 6abc<\/p>\n

Question 5.
\nObtain the product of
\n(i) xy, yz, zx
\n(ii) a, -a2<\/sup>, a3<\/sup>
\n(iii) 2, 4y, 8y2<\/sup>, 16y3<\/sup>
\n(iv) a, 2b, 3c, 6abc
\n(v) m, -mn, mnp
\nSolution:
\n(i) xy, yz, zx
\n(xy) \u00d7 (yz) \u00d7 (zx)
\n= (x \u00d7 x) \u00d7 (y \u00d7 y) \u00d7 (z \u00d7 z)
\n= x2<\/sup> \u00d7 y2<\/sup> \u00d7 z2<\/sup>
\n= x2<\/sup>y2<\/sup>z2<\/sup><\/p>\n

(ii) a; -a2<\/sup>; a3<\/sup>
\n(a) \u00d7 (-a2<\/sup>) \u00d7 (a3<\/sup>)
\n= -(a \u00d7 a2<\/sup> \u00d7 a3<\/sup>)
\n= -a6<\/sup><\/p>\n

(iii) 2, 4y, 8y2<\/sup>, 16y3<\/sup>
\n(2) \u00d7 (4y) \u00d7 (8y2<\/sup>) \u00d7 (16y3<\/sup>)
\n= (2 \u00d7 4 \u00d7 8 \u00d7 16) \u00d7 (y \u00d7 y2<\/sup> \u00d7 y3<\/sup>)
\n= 1024y6<\/sup><\/p>\n

\"NCERT<\/p>\n

(iv) a, 2b, 3c, 6abc
\n(a) \u00d7 (2b) \u00d7 (3c) \u00d7 (6abc)
\n= (2 \u00d7 3 \u00d7 6) \u00d7 (a \u00d7 a) \u00d7 (b \u00d7 b) \u00d7 (c \u00d7 c)
\n= 36 \u00d7 a2<\/sup> \u00d7 b2<\/sup> \u00d7 c2<\/sup>
\n= 36a2<\/sup>b2<\/sup>c2<\/sup><\/p>\n

(v) m, -mn, mnp
\n(m) \u00d7 (-mn) \u00d7 (mnp)
\n= -1 \u00d7 (m \u00d7 m \u00d7 m) \u00d7 (n \u00d7 n) \u00d7 p
\n= -1 \u00d7 m3<\/sup> \u00d7 n2<\/sup> \u00d7 p
\n= -m3<\/sup>n2<\/sup>p<\/p>\n","protected":false},"excerpt":{"rendered":"

These NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Ex 9.2 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Exercise 9.2 Question 1. Find the product of the following pairs of monomials (i) 4, 7p (ii) … Read more<\/a><\/p>\n","protected":false},"author":10,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[7],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/mcqbooks.com\/wp-json\/wp\/v2\/posts\/27737"}],"collection":[{"href":"https:\/\/mcqbooks.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/mcqbooks.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/mcqbooks.com\/wp-json\/wp\/v2\/users\/10"}],"replies":[{"embeddable":true,"href":"https:\/\/mcqbooks.com\/wp-json\/wp\/v2\/comments?post=27737"}],"version-history":[{"count":1,"href":"https:\/\/mcqbooks.com\/wp-json\/wp\/v2\/posts\/27737\/revisions"}],"predecessor-version":[{"id":37282,"href":"https:\/\/mcqbooks.com\/wp-json\/wp\/v2\/posts\/27737\/revisions\/37282"}],"wp:attachment":[{"href":"https:\/\/mcqbooks.com\/wp-json\/wp\/v2\/media?parent=27737"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/mcqbooks.com\/wp-json\/wp\/v2\/categories?post=27737"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/mcqbooks.com\/wp-json\/wp\/v2\/tags?post=27737"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}