NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Ex 6.2

These NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Ex 6.2 Questions and Answers are prepared by our highly skilled subject experts.

NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Exercise 6.2

Question 1.
Find the value of the unknown exterior angle x in the following diagrams:
NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Ex 6.2 1
NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Ex 6.2 2
Answer:
(i) x = 50° + 70°
= 120°
(The exterior angle of a triangle is equal to the sum of its two interior opposite angles)

(ii) x = 45° + 65°
= 110°
(The exterior angle of a triangle is equal to the sum of its two interior opposite angles)

(iii) x = 30° + 40°
= 70°
(The exterior angle of a triangle is equal to the sum of its two interior opposite angles)

(iv) x = 60° + 60°
= 120°
(The exterior angle of a triangle is equal to the sum of its two interior opposite angles)

(v) x = 50° + 50°
= 100°
(The exterior angle of a triangle is equal to the sum of its two interior opposite angles)

(vi) x = 30° + 60°
= 90°
(The exterior angle of a triangle is equal to the sum of its two interior opposite angles)

NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Ex 6.2

Question 2.
Find the value of the unknown interior angle x in the following figures:
NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Ex 6.2 3
Answer:
(i) x + 50°= 115°
x = 115° – 50°
= 65°
(The exterior angle of a triangle is equal to the sum of its two interior opposite angles)

(ii) x + 70° = 100°
x = 100° – 70°
= 30°
(The exterior angle of a triangle is equal to the sum of its two interior opposite angles)

(iii) x + 90° = 125°
x = 125° – 90°
= 35°
(The exterior angle of a triangle is equal to the sum of its two interior opposite angles)

(iv) x + 60° = 120°
x = 120° – 60°
= 60°
(The exterior angle of a triangle is equal to the sum of its two interior opposite angles)

(v) x + 30° = 80°
x = 80° – 30°
= 50°
(The exterior angle of a triangle is equal to the sum of its two interior opposite angles)

(vi) x + 35° = 75°
x = 75° – 35°
= 40°
(The exterior angle of a triangle is equal to the sum of its two interior opposite angles)

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