These NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers InText Questions and Answers are prepared by our highly skilled subject experts.
NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers InText Questions
NCERT Intext Question Page No. 28
Question 1.
Write the predecessor and successor of 19; 1997; 12000; 49; 100000.
Answer:
Predecessor means the number before the given number and Successor is just opposite of it, the number after given number.
Given Number  Predecessor 
Successor 

(i)  19  18  20 
(ii)  1997  1996  1998 
(iii)  12000  11999  12001 
(iv)  49  48  50 
(v)  100000  99999  100001 
Question 2.
Is there any natural number that has no predecessor?
Answer:
Yes, the smallest natural number 1 has no predecessor.
Question 3.
Is there any natural number which has no successor? Is there a last natural number?
Answer:
(i) No, there is no natural number which has no successor.
(ii) No, there is no last natural number.
NCERT Intext Question Page No. 29
Question 1.
Are all natural numbers also whole numbers?
Answer:
Yes, all natural numbers are whole numbers.
Question 2.
Are all whole numbers also natural numbers?
Answer:
No, all whole numbers are not natural numbers. Because 0 is a whole number but it is not a natural number.
Question 3.
Which is the greatest whole number?
Answer:
Since, every whole number has a successor. .’. There is no greatest whole number.
NCERT Intext Question Page No. 30
Question 1.
Find 4 + 5; 2 + 6; 3 + 5 and 1 + 6 using the number line.
Answer:
(i) 4 + 5
Let us start from 4. Since, we have to add 5 to this number, we make 5 jumps to the right. Each jump being equal to 1 unit. After five jumps we reach at 9 (as shown above).
∴ 4 + 5 = 9
(ii) 2 + 6
Let us start from 2. Since, we have to add 6 to this number, we make 6 equal jumps, each jump being equal to 1 unit, to the right and reach to 8.
∴ 2 + 6 = 8
(iii) 3 + 5
We have to add 5 to 3.
∴ start from 3. We make 5 equal jumps. Each jump being equal to 1 unit (as shown in the figure) to the right and reach to 8.
∴ 3 + 5 = 8.
(iv) 3 + 5
As we have to add 6 to 1, therefore, we start from 1 and make 6 equal jumps to the right. Each jump being equal to 1 unit.
We reach to 7.
∴ 1 + 6 = 7
Question 2.
Find 8 3; 6 2; 96 using the number line.
Answer:
(i) 8 – 3
To subtract 3 from 8, start from 8 and make 3 equal jumps towards left. Each jump being equal
i to 1 unit.
So, we reach at 5,
(ii) 6 – 2
To subtract 2 from 6, we start from 6. Make 2 equal jumps towards left. Each jump being equal
to 1 unit.
So, we reach at 4.
(iii) 9 – 6
To subtract 6 from 9, we start from 9. Make 6 equal jumps towards left. Each jump being equal to 1 unit.
So, we reach at 3.
NCERT Intext Question Page No. 31
Question 1.
Find 2 x 6; 3 x 3; 4 x 2 using the number line.
Answer:
(i) 2 x 6
Starting from 0, move 2 units at a time to the right.
Make 6 such moves. So, we reach at 12
∴ 2 x 6 = 12
(ii) 3 x 3
Starting from 0, move 3 units at a time to the right. Make 3 such moves. So, we reach at 9,
∴ 3 x 3 = 9
(iii) 4 x 2
Starting from 0, move 4 units at a time to the right. Make 2 such moves.
So, we reach at 8,
∴ 4 x 2 = 8
NCERT Intext Question Page No. 37
Question 1.
Find: 7 + 18 + 13; 16 + 12 + 4
Answer:
(i) 7 + 18 + 13 = (7 + 13) + 18
= 20 + 18 = 38
(ii) 16 +12 + 4 = (16 + 4) + 12
= 20 + 12 = 32
Question 2.
Find:
25 x 8358 x 4; 625 x 3759 x 8
Answer:
(i) 25 x 8358 x 4 = (25 x 4) x 8358
(Using associativity of whole numbers)
= (100) x 8358 = 835800
(ii) 625 x 3759 x 8 = (625 x 8) x 3759 (Using associativity of whole numbers)
= 500 x 3759
= 5 x 1000 x 3759
= (3759 x 5) x 1000
= 18795 x 1000 = 18795000
∴ 625 x 3759 x 8 = 18795000
NCERT Intext Question Page No. 39
Question 1.
Find 15 x 68; 17 x 23; 69 x 78 + 22 x 69 using distributive property.
Answer:
(i) 15 x 68 = (10 + 5) x 68
= (10 x 68) + (5 x 68)
(By distributivity of multiplication over addition)
= 680 + 340 = 1020
(ii) 17 x 23 = 17 x (20 + 3)
= (17 x 20)+ (17 x 3)
= (17 x 20)+ (17 x 3)
(By distributivity of multiplication over addition)
= 340 + 51 = 391
(iii) 69 x 78 + 22 x 69 = 69 [78 + 22]
= 69 [100]
= 6900
Thus, 69 x 78 + 22 x 69 = 6900
NCERT Intext Question Page No. 42
Question 1.
Which numbers can be shown only as a line?
Answer:
The numbers 2, 5, 7, 11, 13, 14, 17, 19, … can be shown only as a line.
Question 2.
Which can be shown as squares?
Answer:
The numbers 4, 9, 16, 25 … can be shown as squares.
Question 3.
Which can be shown as rectangles?
Answer:
The numbers like 4,6, 8,9,10,12,… can be shown as rectangles.
Question 4.
Write down the first seven numbers that can be arranged as triangles, e.g. 3, 6,.
Answer:
We have
Thus, the first seven triangular numbers are: 3, 6, 10, 15, 21, 28 and 36.
Question 5.
Some numbers can be shown by two rectangles, for example.
There can be many such examples. Some of them are as follows:
Give at least five other such examples.
Answer:
There can be many such examples. Some of them are as follows: