# NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Ex 10.3

These NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Ex 10.3 Questions and Answers are prepared by our highly skilled subject experts.

## NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Exercise 10.3

Question 1.
Find the areas of the rectangles whose sides are:
(a) 3 cm and 4 cm
(b) 12 m and 21 m
(c) 2 km and 3 km
(d) 2 m and 70 cm
(a) Area of rectangle
= 3 cm × 4 cm = 12 cm2

(b) Area of rectangle
= 12 m × 21 m = 252 m2

(c) Area of rectangle
= 2 km × 3 km = 6 km2

(d) Area of rectangle
= 2m ( lm = 100cm)
= 200 cm × 70 cm = 14000sq.cm

Question 2.
Find the areas of the squares whose sides are:
(a) 10 cm
(b) 14 cm
(c) 5 m
(a) Area of square = side × side
= 10 cm × 10 cm = 100 cm2

(b) Area of square = side × side
= 14 cm × 14 cm = 196 cm2

(c) Area of square = side × side
= 5 m × 5 m = 25 m2

Question 3.
The length and breadth of three rectangles are as given below:
(a) 9 m and 6 m
(b) 17 m and 3 m
(c) 4 m and 14 m
Which one has the largest area and which one has the smallest?
(a) Area of rectangle
= 9 m × 6 m = 54 m2

(b) Area of rectangle
= 3 m × 17 m = 51 m2

(c) Area of rectangle
= 4 m × 14 m = 56 m2
Thus, the rectangle (c) has largest area, and rectangle (b) has smallest area.

Question 4.
The area of a rectangular garden 50 m long is 300 sq m. Find the width of the garden.
Length of rectangle
= 50 m and Area of rectangle = 300 m2 Since, Area of rectangle
$$\frac{\text { Area of rectangle }}{\text { Length }}$$ = $$\frac{300}{50}$$ = 6m
Thus, the breadth of the garden is 6 m.

Question 5.
What is the cost of tiling a rectangular plot of land 500 m long and 200 m wide at the rate of ₹ 8 per hundred sq m?
Length of land
= 500 m and Breadth of land = 200 m
Area of land = length × breadth
= 500 m × 200 m = 1,00,000 m2
Cost of tilling 100 sq. m of land = 8
∴ Cost of tilling 1,00,000 sq. m of land
$$\frac{8 \times 100000}{100}$$ = 8000

Question 6.
A table-top measures 2 m by 1 m 50 cm. What is its area in square metres?
Length of table = 2 m
Breadth of table = 1 m 50 cm = 1.50 m
Area of table = length × breadth
= 2 m × 1.50 m = 3 m2

Question 7.
A room is 4 m long and 3 m 50 cm wide. How many square metres of carpet is needed to cover the floor of the room?
Length of room = 4 m
Breadth of room = 3 m 50 cm = 3.50 m
Area of carpet = length × breadth
= 4 × 3.50= 14 m2

Question 8.
A floor is 5 m long and 4 m wide. A square carpet of sides 3 m is laid on the floor. Find the area of the floor that is not carpeted.
Length of floor
= 5 m and breadth of floor = 4 m
Area of floor = length × breadth
= 5m × 4m = 20m2
Now, Side of square carpet = 3 m
Area of square carpet = side × side
= 3 × 3 = 9 m2
Area of floor that is not carpeted = 20m2 – 9m2 = 11m2

Question 9.
Five square flower beds each of sides 1 m are dug on a piece of land 5 m long and 4 m wide. What is the area of the remaining part of the land?
Side of square bed = 1 m
Area of square bed = side × side
= 1m × 1m = 1m2
∴ Area of 5 square beds = 1 × 5 = 5 m2
Now, Length of land = 5 m
Breadth of land = 4 m
∴ Area of land = length × breadth
= 5 m × 4 m = 20 m2
Area of remaining part
= Area of land – Area of 5 flower beds = 20 m2 – 5 m2 = 15 m2

Question 10.
By splitting the following figures into rectangles, find their areas (The measures are given in centimetres).

Area of HKLM = 3 × 3 = 9 cm2
Area of IJGH = 1 × 2 = 2 cm2
Area of FEDG = 3 × 3 = 9 cm2
Area of ABCD = 2 × 4 = 8 cm2
Total area of the figure
= 9 + 2 +9 + 8
= 28 cm2

Area of ABCD = 3 × 1 = 3 cm2
Area of BDEF = 3 × 1 = 3 cm2
Area of FGHI = 3 × 1 = 3 cm2
Total area of the figure = 3 + 3 + 3 = 9 cm2

Question 11.
Split the following shapes into rectangles and find their areas. (The measures are given in centimetres)

(a) Area of rectangle ABCD
= 2 × 10 = 20 cm2
Area of rectangle DEFG
= 10 × 2 = 20 cm2
Total area of the figure
= 20 + 20 = 40 cm2

(b) There are 5 squares each of side 7 cm.
Area of one square
= 7 × 7 = 49 cm2
Area of 5 square
= 49 × 5 = 245 cm2

(c) Area of rectangle ABCD
= 5 × 1 = 5 cm2
Area of rectangle EFGH
= 4 × 1 = 4 cm2
Total area of the figure
= 5 + 4 cm2

Question 12.
How many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively:
(a) 100 cm and 144 cm
(b) 70 cm and 36 cm
(a) Area of region
= 100 cm × 144 cm = 14400 cm2
Area of one tile
= 5 cm × 12 cm = 60 cm2
Number of tiles = $$\frac{\text { Area of region }}{\text { Area of one tile }}$$ = $$\frac{14400}{60}$$ = 240
Thus, 240 tiles are required.

(b) Area of region
= 70 cm × 36 cm = 2520 cm2
Area of one tile
= 5 cm × 12 cm = 60 cm2
Number of tiles
= $$\frac{\text { Area of region }}{\text { Area of one tile }}$$ = $$\frac{2520}{60}$$ = 42
Thus, 42 tiles are required.

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